Unable to create default value for DICTIONARY function argument
Description
The enclosed code demonstrates an attempt at making a DICTIONARY function argument optional, with an empty dictionary. It fails on syntax-check with the following error:
The commented-out function, without a default argument, works well.
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Gavin Halliday September 28, 2017 at 12:54 PM
The fix is trivial - I will release to 6.4.4
Fixed
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The enclosed code demonstrates an attempt at making a DICTIONARY function argument optional, with an empty dictionary. It fails on syntax-check with the following error:
The commented-out function, without a default argument, works well.